2q^2-60q-50=0

Solution for 2q^2-60q-50=0 equation:

2q^2-60q-50=0

a = 2; b = -60; c = -50;
Δ = b2-4ac
Δ = -602-4·2·(-50)
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-20\sqrt{10}}{2*2}=\frac{60-20\sqrt{10}}{4}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+20\sqrt{10}}{2*2}=\frac{60+20\sqrt{10}}{4}
$